NEWTON BACKWARD INTERPOLATION( NUMERICAL METHODS)

// Newton Backward Interpolation
#include<stdio.h>
#include<conio.h>
int main()
{
  int i,j,num;
  float data[10][10],u,abc,x,ch1=0.0,ch=1;
  //char str[80];
  printf("\n *** Welcome to the calculation in Newton Backward Interpolation***");
  printf("\n\n Enter the number of values do u wanna Enter:\n Enter Your Choice:");
  scanf("%d",&num);
  printf("\n\n Enter the set of data values:");
  for(i=0;i<num;i++)
  {
  printf("\n Enter  data value x(%d) is:",i+1);
  scanf("%f",&data[i][0]);
  }
  printf("\n\n\t *** Enter The Set Of Function Values ***");
  for(i=0;i<num;i++)
  {
  printf("\n Enter function value y(%d)is:",i+1);
  scanf("%f",&data[i][1]);
  }
  for(j=2;j<num+1;j++)
  {
   for(i=0;i<num-1;i++)
   {
   data[i][j]=((data[i+1][j-1])-(data[i][j-1]));
   }
  }
   printf("\n The Newton Backward difference Table is:");
   printf("\n x        f(x) ");
   for(i=0;i<num;i++)
   {
   printf("       %dDD  ",i);
    // if(i==4)
    // break;
   }
   for(i=0;i<num;i++)
   {
    printf("\n");
    for(j=0;j<num+1-i;j++)
    {
    printf(" %f",data[i][j]);
    }
     }
    printf("\n\n Enter the value of x:\n Enter Your Choice:");
    scanf("%f",&x);
    abc=((data[num-1][0])-(data[num-2][0]));
    u=((x)-(data[num-1][0]))/abc;
    ch1=data[num-1][1];
    for(i=1;i<num;i++)
    {
    ch=ch*((u+(i-1))/(i));
    //ch1=ch1+(data[0][i+1])*(ch);
    ch1=ch1+((data[num-i-1][i+1])*(ch));
    }
    printf("\n\n\t Hence The value at the function at x=%f is =%f",x,ch1);
    printf("\n\n\t\t\t *** Bye Bye ***");
  getch();
  return 0;
}
Gurpreet Singh